2/3x^2=4/5x

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Solution for 2/3x^2=4/5x equation: 


x in (-oo:+oo)

(2/3)*x^2 = (4/5)*x // - (4/5)*x

(2/3)*x^2-((4/5)*x) = 0

(2/3)*x^2+(-4/5)*x = 0

2/3*x^2-4/5*x = 0

DELTA = (-4/5)^2-(0*2/3*4)

DELTA = 16/25

DELTA > 0

x = ((16/25)^(1/2)+4/5)/(2/3*2) or x = (4/5-(16/25)^(1/2))/(2/3*2)

x = 6/5 or x = 0

x in { 0, 6/5 }

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